2m^2+13m-7=0

Solution for 2m^2+13m-7=0 equation:

2m^2+13m-7=0

a = 2; b = 13; c = -7;
Δ = b2-4ac
Δ = 132-4·2·(-7)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-15}{2*2}=\frac{-28}{4}
=-7
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+15}{2*2}=\frac{2}{4}
=1/2
$